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<title>Introduction to Java Programming, 10E, Y. Daniel Liang</title>
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<script>var answer0 = 'False. <br />
A subclass is an extension of a superclass and normally contains more details information than its superclass.
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document.getElementById('b0').style.background = 'green'; document.getElementById('b0').innerHTML = 'Show Answer';} }</script>
<script>var answer1 = 'The extends keyword is used to define a subclass that extends a superclass.
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document.getElementById('b1').style.background = 'green'; document.getElementById('b1').innerHTML = 'Show Answer';} }</script>
<script>var answer2 = 'Single inheritance allows a subclass to extend only one superclass. Multiple inheritance allows a subclass to extend multiple classes. Java does not allow multiple inheritance.
java程序基础复习题';function submit2() {if (document.getElementById('b2').innerHTML == 'Show Answer') {document.getElementById('a2').innerHTML = answer2;document.getElementById('b2').style.background = 'gray'; document.getElementById('b2').innerHTML = 'Hide Answer'; }else {document.getElementById('a2').innerHTML = '';
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<script>var answer3 = '(a) The output is
<pre>
A's no-arg constructor is invoked
</pre>
(b) The default constructor of B attempts to invoke the default of constructor of A, but class A's default constructor is not defined.
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document.getElementById('b3').style.background = 'green'; document.getElementById('b3').innerHTML = 'Show Answer';} }</script>
<script>var answer4 = 'A subclass can explicitly invoke a suplerclass's constructor using the super keyword.
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<script>var answer5 = 'False. <br />
If a subclass's constructor explicitly invoke a superclass's constructor, the superclass's no-arg constructor is not invoked.
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<script>var answer6 = 'False. <br />
You can only override accessible instance methods.
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<script>var answer7 = 'False. <br />
You can only override accessible instance methods.
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<script>var answer8 = 'Use super() or super(args). This statement must be the first in the constructor in the subclass.
';function submit8() {if (document.getElementById('b8').innerHTML == 'Show Answer') {document.getElementById('a8').innerHTML = answer8;document.getElementById('b8').style.background = 'gray'; document.getElementById('b8').innerHTML = 'Hide Answer'; }else {document.getElementById('a8').innerHTML = '';
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<script>var answer9 = 'Use super.method() or super.method(args).
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<script>var answer10 = 'The following lines are erroneous:
<pre>
{
radius = radius; // Must use this.radius = radius
}
class B extends Circle
{
Circle(radius); // Must use super(radius)
length = length; // Must use this.length = length
}
public double getArea()
{
return getArea()*length; // super.getArea()
}
</pre>
';function submit10() {if (document.getElementById('b10').innerHTML == 'Show Answer') {document.getElementById('a10').innerHTML = answer10;document.getElementById('b10').style.background = 'gray'; document.getElementById('b10').innerHTML = 'Hide Answer'; }else {document.getElementById('a10').innerHTML = '';
document.getElementById('b10').style.background = 'green'; document.getElementById('b10').innerHTML = 'Show Answer';} }</script>
<script>var answer11 = 'Method overloading defines methods of the same name in a class. Method overriding modifies the methods that are defined in the superclasses.
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<script>var answer12 = 'It is method overridden.
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