sql数据库面试必会6题经典_sql笔试题及答案

数据库 (2) 2024-08-12 16:12

Hi,大家好,我是编程小6,很荣幸遇见你,我把这些年在开发过程中遇到的问题或想法写出来,今天说一说
sql数据库面试必会6题经典_sql笔试题及答案,希望能够帮助你!!!。

SQL数据库面试题以及答案(50例题)

Student(Sid,Sname,Sage,Ssex)学生表 Sid:学号 Sname:学生姓名 Sage:学生年龄 Ssex:学生性别 Course(Cid,Cname,T#)课程表 Cid:课程编号 Cname:课程名称 Tid:教师编号 SC(Sid,Cid,score)成绩表 Sid:学号 Cid:课程编号 score:成绩 Teacher(Tid,Tname)教师表 Tid:教师编号: Tname:教师名字 

问题:

1、查询“001”课程比“002”课程成绩高的所有学生的学号
select a.sid from (select sid,score from sc where cid='001')a, (select sid,score from sc where cid='002')b where a.sid = b.sid and a.score>b.score;
2、查询平均成绩大于60分的同学的学号和平均成绩
select sid,avg(score) from sc group by sid having avg(score)>60;
3、查询所有同学的学号、姓名、选课数、总成绩
select s.sid,s.sname,count_cid as 选课数, sum_score as 总成绩 from student s left join (select sid,count(cid) as count_cid,sum(score) as sum_score from sc group by sid )sc on s.sid = sc.sid;
4、查询姓‘李’的老师的个数:
select count(tname) from teacher where tname like '李%';
5、查询没有学过“叶平”老师可的同学的学号、姓名:
select s.sid,s.sname from student as s where s.sid not in ( select DISTINCT sid from sc as sc where sc.cid in ( select cid from course as c left join teacher as t on c.tid = t.tid where t.tname = '叶平') );
6、查询学过“叶平”老师所教的所有课的同学的学号、姓名:
select s.sid,s.sname from student as s where s.sid in ( select distinct sc.sid from sc as sc where sc.cid in ( select cid from course as c left join teacher as t on c.tid = t.tid where t.tname = '叶平') group by sc.sid HAVING count(cid)= (select count(cid) from course as c left join teacher as t on c.tid = t.tid where t.tname = '叶平') );
7、查询学过“011”并且也学过编号“002”课程的同学的学号、姓名:
SELECT s.sid,s.sname from student as s left join sc as sc on s.sid = sc.sid where sc.cid = '001' and EXISTS( select * from sc as sc_2 where sc.sid = sc_2.sid and sc_2.cid='002'); select s.sid,s.sname from student as s left join sc as sc on sc.sid = s.sid where sc.cid = '001' and s.sid in ( select sid from sc as sc_2 where sc_2.cid='002' and sc_2.sid = sc.sid);
8、查询课程编号“002”的成绩比课程编号“001”课程低的所有同学的学号、姓名:
select sid,sname from (select student.sid,student.sname,score, (select score from sc as sc_2 where sc_2.sid = student.sid and sc_2.cid = '002') as score2 from student,sc where student.sid=sc.sid and cid = '001') s_2 where score2<score;
9、查询所有课程成绩小于60的同学的学号、姓名:
select sid,sname from student where sid not in (select s.sid from student s,sc where s.sid=sc.sid and score>60 ); select sid,sname from student s where not EXISTS ( select s.sid from sc where sc.sid = s.sid and sc.score>60);
10、查询没有学全所有课的同学的学号、姓名:
select s.sid,s.sname from student s ,sc sc where s.sid = sc.sid group by s.sid,s.sname having count(sc.cid)<( select count(cid) from course); select s.sid,s.sname from student s right join sc sc on s.sid = sc.sid group by s.sid,s.sname having count(sc.cid)< (select count(cid) from course);
11、查询至少有一门课与学号为“1001”同学所学相同的同学的学号和姓名:
select student.sid,sname from student,sc where student.sid = sc.sid and cid in (select cid from sc where sid='1001'); select s.sid,s.sname from sc sc left join student as s on sc.sid = s.sid where sc.cid in (select cid from sc where sid='1001'); select sc_1.sid,s.sname from sc sc_1 left join student as s on sc_1.sid = s.sid where exists (select sc_2.cid from sc as sc_2 where sc_1.cid = sc_2.cid and sc_2.sid = '1001');
12、查询至少学过学号为“001”同学所有一门课的其他同学学号和姓名;
13、把“SC”表中“叶平”老师教的课的成绩都更改为此课程的平均成绩:
update sc set score = (select avg(sc_2.score) from sc sc_2 where sc_2.cid = sc.cid) where cid in (select c.cid from course c left join teacher t on t.tid = c.tid where t.tname = '叶平');
14、查询和“1002”号的同学学习的课程完全相同的其他同学学号和姓名:
select sc_1.sid from (select cid from sc where sid='1002')a left join sc sc_1 on a.cid = sc_1.cid where sc_1.sid<>'1002' group by sc_1.sid having count(sc_1.cid) = (select count(cid) from sc where sid='1002'); select a.sid,s.sname from (select sid,GROUP_CONCAT(cid order by cid separator ',') as cid_str from sc where sid='1002')b, (select sid,GROUP_CONCAT(cid order by cid separator ',') as cid_str from sc group by sid)a left join student s on a.sid = s.sid where a.cid_str = b.cid_str and a.sid<>'1002';
15、删除学习“叶平”老师课的SC表记录:
delete from sc WHERE cid in ( select c.cid from course c LEFT JOIN teacher t on c.tid=t.tid where t.tname = '叶平');
16、向SC表中插入一些记录,这些记录要求符合以下条件:没有上过编号“003”课程的同学学号、002号课的平均成绩:
insert into sc select sid,'002', (select avg(score) from sc where cid='0022') from student where sid not in (select sid from sc where cid='002');
17、按平均成绩从高到低显示所有学生的“数据库”、“企业管理”、“英语”三门的课程成绩,按如下形式显示:学生ID,数据库,企业管理,英语,有效课程数,有效平均分:
select sid as 学生id, (SELECT score from sc where sc.sid = t.sid and cid='004') as 数据库, (select score from sc where sc.sid = t.sid and cid='001') as 企业管理, (select score from sc where sc.sid = t.sid and cid='015') as 英语, count(cid) as 有效课程数, avg(t.score) as 平均成绩 from sc as t group by sid order by avg(t.score);
18、查询各科成绩最高和最低的分:以如下的形式显示:课程ID,最高分,最低分
select l.cid as 课程id,l.score as 最高分, r.score as 最低分 from sc l,sc r where l.cid = r.cid and l.score = (select max(t.score) from sc t where l.cid = t.cid group by t.cid) and r.score = (select min(t.score) from sc t where r.cid = t.cid group by t.cid) order by l.cid; select cid as 课程id,max(score) as 最高分, min(score) as 最低分 from sc group by cid;
19、按各科平均成绩从低到高和及格率的百分数从高到低顺序:
SELECT t.cid as 课程号, c.cname as 课程名, COALESCE(avg(score),0) as 平均成绩, 100*sum(case when COALESCE(score,0)>=60 then 1 else 0 END)/count(*) as 及格百分数 from sc t left join course c on t.cid = c.cid group by t.cid order by 100*sum(case when COALESCE(score,0)>=60 then 1 else 0 END)/count(*);
20、查询如下课程平均成绩和及格率的百分数(用”1行”显示): 企业管理(001),马克思(002),OO&UML (003),数据库(004):
21、查询不同老师所教不同课程平均分从高到低显示:
select t.tid as 教师id, t.tname as 教师姓名, sc.cid as 课程id, avg(score) as 平均成绩 from sc as sc LEFT JOIN course c on sc.cid = c.cid left join teacher t on c.tid = t.tid group by sc.cid order by avg(sc.score) desc;
22、查询如下课程成绩第3名到第6名的学生成绩单:企业管理(001),马克思(002),UML(003),数据库(004):
23、统计下列各科成绩,各分数段人数:课程ID,课程名称,[100-85],[85-70],[70-60],[ 小于60] :
select sc.cid as 课程id,cname as 课程名称, sum(case when score between 85 and 100 then 1 else 0 end) as '[100-85]', sum(case when score between 70 and 85 then 1 else 0 end) as '[85-70]', sum(case when score between 60 and 70 then 1 else 0 end) as '[70-60]', sum(case when score<60 then 1 else 0 end) as '[60-0]' from sc as sc left join course as c on sc.cid = c.cid group by sc.cid;
24、查询学生平均成绩及其名次:
select 1+(select count(distinct 平均成绩) from (select sid,avg(score) as 平均成绩 from sc group by sid)t1 where 平均成绩>t2.平均成绩) as 名次, sid as 学生学号,平均成绩 from (select sid,avg(score) 平均成绩 from sc group by sid) as t2 order by 平均成绩 desc;
25、查询各科成绩前三名的记录(不考虑成绩并列情况):
select sid,cid,score from sc sc_1 where ( select count(3) from sc sc_2 where sc_1.cid = sc_2.cid and sc_2.score>=sc_1.score)<=2 order by sc_1.cid );
26、查询每门课程被选修的学生数:
select cid, count(sid) from sc group by cid;
27、查询出只选修一门课程的全部学生的学号和姓名:
select sc.sid,s.sname, count(sc.cid) as 课程数 from sc as sc LEFT JOIN student as s on sc.sid = s.sid group by sc.sid having count(sc.cid)=1;
28、查询男生、女生人数:
select count(ssex) as 男生人数 from student group by ssex having ssex = '男'; select count(2) from student where ssex = '女';
29、查询姓“张”的学生名单:
select sid,sname from student where sname like '张%';
30、查询同名同姓的学生名单,并统计同名人数:
select sname,count(8) from student group by sname having count(8)>1;
31、1981年出生的学生名单(注:student表中sage列的类型是datetime):
32、查询平均成绩大于85的所有学生的学号、姓名和平均成绩:
select s.sname,sc.sid,avg(sc.score) as 平均成绩 from sc as sc left join student as s on sc.sid = s.sid group by sc.sid having avg(sc.score)>85;
33、查询每门课程的平均成绩,结果按平均成绩升序排序,平均成绩相同时,按课程号降序排列:
select cid,avg(score) from sc group by cid order by avg(score),cid desc;
34、查询课程名称为“数据库”,且分数低于60的学生名字和分数:
select c.cname,s.sid,s.sname,sc.score from course c left join sc on sc.cid = c.cid LEFT JOIN student s on s.sid = sc.sid where c.cname = '数据库' and sc.score<60;
35、查询所有学生的选课情况:
select sc.sid,sc.cid,s.sname,c.cname from sc LEFT JOIN course c on sc.cid = c.cid left join student s on sc.sid = s.sid;
36、查询任何一门课程成绩在70分以上的姓名、课程名称和分数:
select distinct s.sid,s.sname,sc.cid,sc.score from sc left join student s on sc.sid = s.sid left join course c on sc.cid = c.cid where sc.score>70;
37、查询不及格的课程,并按课程号从大到小的排列:
select cid from sc where score<60 ORDER BY cid;
38、查询课程编号为“003”且课程成绩在80分以上的学生的学号和姓名:
select sc.sid,s.sname from sc left join student s on sc.sid = s.sid where sc.cid = '003' and sc.score>80;
39、求选了课程的学生人数:
select count(2) from (select distinct sid from sc)a;
40、查询选修“叶平”老师所授课程的学生中,成绩最高的学生姓名及其成绩:
select s.sname,sc.score from sc sc left join student s on sc.sid = s.sid left join course c on sc.cid = c.cid left join teacher t on c.tid = t.tid where t.tname = '叶平' and sc.score = ( select max(score) from sc sc_1 where sc.cid = sc_1.cid);
41、查询各个课程及相应的选修人数:
select cid,count(*) from sc group by cid;
42、查询不同课程成绩相同的学生和学号、课程号、学生成绩:
select DISTINCT a.sid,a.cid,a.score from sc as a ,sc as b where a.score = b.score and a.cid <> b.cid;
43、查询每门课程成绩最好的前两名:
44、统计每门课程的学生选修人数(超过10人的课程才统计)。要求输出课程号和选修人数,查询结果按人数降序排序,若人数相同,按课程号升序排序:
select cid as 课程号,count(8) as 选修人数 from sc group by cid HAVING count(sid)>10 order by count(8) desc,cid;
45、检索至少选修两门课程的学生学号:
select sid from sc group by sid having count(8)>=2;
46、查询全部学生选修的课程和课程号和课程名:
select cid,cname from course where cid in (select cid from sc group by cid);
47、查询没学过”叶平”老师讲授的任一门课程的学生姓名:
select sname from student where sid not in ( select sid from sc,course,teacher where course.tid = teacher.tid and sc.cid = course.cid and teacher.tname='叶平' );
48、查询两门以上不及格课程的同学的学号以及其平均成绩:
select sid,avg(COALESCE(score,0)) from sc where sid in ( select sid from sc where score<60 group by sid having count(8)>2 ) group by sid;
49、检索“004”课程分数小于60,按分数降序排列的同学学号:
select sid,score from sc where cid='004' and score<60 order by score desc;
50、删除“002”同学的“001”课程的成绩:
delete from sc where sid = '002' and cid = '001';

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