Hi，大家好，我是编程小6，很荣幸遇见你，我把这些年在开发过程中遇到的问题或想法写出来，今天说一说
myeclipse8.6注册码_eclipse for java developers,希望能够帮助你!!!。

//一个用Java写的MyEclipse6.5的注册码计算程序;

//最后有一个算好的，也可以自己算自己的;

//本程序只供参考学习用;

import java.text.DecimalFormat;
import java.text.NumberFormat;
import java.text.SimpleDateFormat;
import java.util.Calendar;

public class Crack {

public static final void main(String[] args) {

   String id = "Lisifu"; //这里可以改为你想要的用户名
   String num = "999";
   System.out.println(getSerial(id, "100", num, false));
}

public static String getSerial(String userId, String version,
    String licenseNum, boolean selected) {

   Calendar cal = Calendar.getInstance();
   cal.add(1, 3);
   cal.add(6, -1);
   NumberFormat nf = new DecimalFormat("000");
   licenseNum = nf.format(Integer.valueOf(licenseNum));
   String verTime = selected ? (new StringBuffer("-")).append(
     (new SimpleDateFormat("yyMMdd")).format(cal.getTime())).append(
     "0").toString() : "-0";
   String type = "YE3MB-";
   String need = (new StringBuffer(String.valueOf(userId.substring(0, 1))))
     .append(type).append(version).append(licenseNum)
     .append(verTime).toString();
   String dx = (new StringBuffer(String.valueOf(need)))
     .append(
       "Decompiling this copyrighted software is a violation of both your license agreement and the Digital Millenium Copyright Act of 1998 (http://www.loc.gov/copyright/legislation/dmca.pdf). Under section 1204 of the DMCA, penalties range up to a $500,000 fine or up to five years imprisonment for a first offense. Think about it; pay for a license, avoid prosecution, and feel better about yourself.")

     .append(userId).toString();
   int suf = decode(dx);
   String code = (new StringBuffer(String.valueOf(need))).append(
     String.valueOf(suf)).toString();
   return change(code);
}

private static int decode(String s) {

   int i = 0;
   char ac[] = s.toCharArray();
   int j = 0;
   for (int k = ac.length; j < k; j++)
    i = 31 * i + ac[j];

   return Math.abs(i);
}

private static String change(String s) {

   byte abyte0[] = s.getBytes();
   char ac[] = new char[s.length()];
   int i = 0;
   for (int k = abyte0.length; i < k; i++) {

    int j = abyte0[i];
    if (j >= 48 && j <= 57)
     j = ((j - 48) + 5) % 10 + 48;
    else if (j >= 65 && j <= 90)
     j = ((j - 65) + 13) % 26 + 65;
    else if (j >= 97 && j <= 122)
     j = ((j - 97) + 13) % 26 + 97;
    ac[i] = (char) j;
   }

   return String.valueOf(ac);
}
}

结果为：

Subscriber:Lisifu
Subscription Code:YLR8ZO--

今天的分享到此就结束了，感谢您的阅读，如果确实帮到您，您可以动动手指转发给其他人。